olymmath

HMMT 2018 U8

  • Guts
  • Answer

Suppose a real number x>1x>1 satisfies

log⁡2(log⁡4x)+log⁡4(log⁡16x)+log⁡16(log⁡2x)=0\log _{2}\left(\log _{4} x\right)+\log _{4}\left(\log _{16} x\right)+\log _{16}\left(\log _{2} x\right)=0

Compute

log⁡2(log⁡16x)+log⁡16(log⁡4x)+log⁡4(log⁡2x)\log _{2}\left(\log _{16} x\right)+\log _{16}\left(\log _{4} x\right)+\log _{4}\left(\log _{2} x\right)

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

-\frac{1}{4}

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmmt/2018/u8 · Tag 725ZTT0BST · Edit this page on GitHub · Keys: j next, k previous