olymmath

KöMaL 2020 B5079

    Solve the equation log⁡2log⁡3x+log⁡3log⁡2x=log⁡26log⁡23\log_2 \log_3 x+\log_3\log_2 x=\log_2\frac{6}{\log_2 3} over the set of real numbers.

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