olymmath

ISL 2019 G3

    In triangle ABCA B C, let A1A_{1} and B1B_{1} be two points on sides BCB C and ACA C, and let PP and QQ be two points on segments AA1A A_{1} and BB1B B_{1}, respectively, so that line PQP Q is parallel to ABA B. On ray PB1P B_{1}, beyond B1B_{1}, let P1P_{1} be a point so that ∠PP1C=∠BAC\angle P P_{1} C=\angle B A C. Similarly, on ray QA1Q A_{1}, beyond A1A_{1}, let Q1Q_{1} be a point so that ∠CQ1Q=∠CBA\angle C Q_{1} Q=\angle C B A. Show that points P,Q,P1P, Q, P_{1}, and Q1Q_{1} are concyclic. (Ukraine)

    Official text Transcription from NuminaMath olympiads, checked word for word against the official paper. Quoted with source.

    Official text: IMO 2019 Shortlist booklet, page 10.

    Solutions

    Official solution Solution 1 by the IMO Problem Selection Committee

    The terms of the source let olymmath link to this solution but not copy it. Read the solution (IMO official site).

    Locator isl/2019/g3 · Tag AYMVEAAZTW · Edit this page on GitHub · Keys: j next, k previous