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HMMT 2015 U10

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Let b(x)=x2+x+1b(x)=x^{2}+x+1. The polynomial x2015+x2014+⋯+x+1x^{2015}+x^{2014}+\cdots+x+1 has a unique "base b(x)b(x) " representation x2015+x2014+⋯+x+1=∑k=0Nak(x)b(x)kx^{2015}+x^{2014}+\cdots+x+1=\sum_{k=0}^{N} a_{k}(x) b(x)^{k} where

  • NN is a nonnegative integer;
  • each "digit" ak(x)a_{k}(x) (for 0≤k≤N0 \leq k \leq N ) is either the zero polynomial (i.e. ak(x)=0a_{k}(x)=0 ) or a nonzero polynomial of degree less than deg⁡b=2\operatorname{deg} b=2; and
  • the "leading digit aN(x)a_{N}(x) " is nonzero (i.e. not the zero polynomial).

Find aN(0)a_{N}(0) (the "leading digit evaluated at 0 ").

Dataset text NuminaMath olympiads. Quoted with source.

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