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HMMT 2015 T9

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Let z=e2πi101z=e^{\frac{2 \pi i}{101}} and let ω=e2πi10\omega=e^{\frac{2 \pi i}{10}}. Prove that

∏a=09∏b=0100∏c=0100(ωa+zb+zc)\prod_{a=0}^{9} \prod_{b=0}^{100} \prod_{c=0}^{100}\left(\omega^{a}+z^{b}+z^{c}\right)

is an integer and find (with proof) its remainder upon division by 101.

Dataset text NuminaMath olympiads. Quoted with source.

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