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HMMT 2015 T1

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The complex numbers x,y,zx, y, z satisfy

xyz=−4(x+1)(y+1)(z+1)=7(x+2)(y+2)(z+2)=−3\begin{aligned} x y z & =-4 \\ (x+1)(y+1)(z+1) & =7 \\ (x+2)(y+2)(z+2) & =-3 \end{aligned}

Find, with proof, the value of (x+3)(y+3)(z+3)(x+3)(y+3)(z+3).

Dataset text NuminaMath olympiads. Quoted with source.

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