olymmath

HMMT 2015 G3

  • Geometry
  • Answer

Let ABCDA B C D be a quadrilateral with ∠BAD=∠ABC=90∘\angle B A D=\angle A B C=90^{\circ}, and suppose AB=BC=1,AD=2A B=B C=1, A D=2. The circumcircle of ABCA B C meets AD‾\overline{A D} and BD‾\overline{B D} at points EE and FF, respectively. If lines AFA F and CDC D meet at KK, compute EKE K.

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

\frac{\sqrt{2}}{2}

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmmt/2015/g3 · Tag WXZF8WKAPJ · Edit this page on GitHub · Keys: j next, k previous