olymmath

HMMT 2014 T4

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  • Answer

Compute

∑k=0100⌊2100250+2k⌋\sum_{k=0}^{100}\left\lfloor\frac{2^{100}}{2^{50}+2^{k}}\right\rfloor

(Here, if xx is a real number, then ⌊x⌋\lfloor x\rfloor denotes the largest integer less than or equal to xx.)

Dataset text NuminaMath olympiads. Quoted with source.

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101 \cdot 2^{49}-50

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