Home Competitions HMMT 2013 G9
Pentagon A B C D E A B C D E A B C D E is given with the following conditions:
(a) ∠ C B D + ∠ D A E = ∠ B A D = 45 ∘ , ∠ B C D + ∠ D E A = 300 ∘ \angle C B D+\angle D A E=\angle B A D=45^{\circ}, \angle B C D+\angle D E A=300^{\circ} ∠ C B D + ∠ D A E = ∠ B A D = 4 5 ∘ , ∠ B C D + ∠ D E A = 30 0 ∘
(b) B A D A = 2 2 3 , C D = 7 5 3 \frac{B A}{D A}=\frac{2 \sqrt{2}}{3}, C D=\frac{7 \sqrt{5}}{3} D A B A = 3 2 2 , C D = 3 7 5 , and D E = 15 2 4 D E=\frac{15 \sqrt{2}}{4} D E = 4 15 2
(c) A D 2 ⋅ B C = A B ⋅ A E ⋅ B D A D^{2} \cdot B C=A B \cdot A E \cdot B D A D 2 ⋅ B C = A B ⋅ A E ⋅ B D
Compute B D B D B D .
Dataset text NuminaMath olympiads . Quoted with source.
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