olymmath

HMMT 2006 U5

  • Guts
  • Answer

Find the number of solutions in positive integers (k;a1,a2,…,ak;b1,b2,…,bk)\left(k ; a_{1}, a_{2}, \ldots, a_{k} ; b_{1}, b_{2}, \ldots, b_{k}\right) to the equation

a1(b1)+a2(b1+b2)+⋯+ak(b1+b2+⋯+bk)=7.a_{1}\left(b_{1}\right)+a_{2}\left(b_{1}+b_{2}\right)+\cdots+a_{k}\left(b_{1}+b_{2}+\cdots+b_{k}\right)=7 .

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

15

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmmt/2006/u5 · Tag 7E4NE25S8P · Edit this page on GitHub · Keys: j next, k previous