olymmath

HMMT 2006 G8

  • Geometry
  • Answer

Triangle ABCA B C has a right angle at BB. Point DD lies on side BCB C such that 3∠BAD=3 \angle B A D= ∠BAC\angle B A C. Given AC=2A C=2 and CD=1C D=1, compute BDB D.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{3}{8}

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