olymmath

HMMT 2005 U28

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There are three pairs of real numbers (x1,y1),(x2,y2)\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right), and (x3,y3)\left(x_{3}, y_{3}\right) that satisfy both x3−3xy2=2005x^{3}-3 x y^{2}=2005 and y3−3x2y=2004y^{3}-3 x^{2} y=2004. Compute (1−x1y1)(1−x2y2)(1−x3y3)\left(1-\frac{x_{1}}{y_{1}}\right)\left(1-\frac{x_{2}}{y_{2}}\right)\left(1-\frac{x_{3}}{y_{3}}\right).

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{1}{1002}

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