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HMMT 2005 G10

  • Geometry
  • Answer

Let ABA B be the diameter of a semicircle Γ\Gamma. Two circles, ω1\omega_{1} and ω2\omega_{2}, externally tangent to each other and internally tangent to Γ\Gamma, are tangent to the line ABA B at PP and QQ, respectively, and to semicircular arc ABA B at CC and DD, respectively, with AP<AQA P<A Q. Suppose FF lies on Γ\Gamma such that ∠FQB=∠CQA\angle F Q B=\angle C Q A and that ∠ABF=80∘\angle A B F=80^{\circ}. Find ∠PDQ\angle P D Q in degrees.

Dataset text NuminaMath olympiads. Quoted with source.

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