olymmath

HMMT 2004 G7

  • Geometry
  • Answer

Yet another trapezoid ABCDA B C D has ADA D parallel to BC.ACB C . A C and BDB D intersect at PP. If [ADP]/[BCP]=1/2[A D P] /[B C P]=1 / 2, find [ADP]/[ABCD][A D P] /[A B C D]. (Here the notation [P1⋯Pn]\left[P_{1} \cdots P_{n}\right] denotes the area of the polygon P1⋯PnP_{1} \cdots P_{n}.)

Dataset text NuminaMath olympiads. Quoted with source.

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3-2 \sqrt{2}

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