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HMIC 2013 Problem 5

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(a) Given a finite set XX of points in the plane, let fX(n)f_{X}(n) be the largest possible area of a polygon with at most nn vertices, all of which are points of XX. Prove that if m,nm, n are integers with m≥n>2m \geq n>2, then fX(m)+fX(n)≥fX(m+1)+fX(n−1)f_{X}(m)+f_{X}(n) \geq f_{X}(m+1)+f_{X}(n-1). (b) Let P0P_{0} be a 1-by-2 rectangle (including its interior), and inductively define the polygon PiP_{i} to be the result of folding Pi−1P_{i-1} over some line that cuts Pi−1P_{i-1} into two connected parts. The diameter of a polygon PiP_{i} is the maximum distance between two points of PiP_{i}. Determine the smallest possible diameter of P2013P_{2013}. (In other words, given a polygon Pi−1P_{i-1}, a fold of Pi−1P_{i-1} consists of a line ll dividing Pi−1P_{i-1} into two connected parts AA and BB, and the folded polygon Pi=A∪BlP_{i}=A \cup B_{l}, where BlB_{l} is the reflection of BB over the line l.)

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{\sqrt{2}}{2^{1006}}

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