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GULF 2014 Problem 3

    (i) ABCABC is a triangle with a right angle at AA , and PP is a point on the hypotenuse BCBC . The line APAP produced beyond PP meets the line through BB which is perpendicular to BCBC at UU . Prove that BU=BABU = BA if, and only if, CP=CACP = CA . (ii) AA is a point on the semicircle CBCB , and points XX and YY are on the line segment BCBC . The line AXAX , produced beyond XX , meets the line through BB which is perpendicular to BCBC at UU . Also the line AYAY , produced beyond YY , meets the line through CC which is perpendicular to BCBC at VV . Given that BY=BABY = BA and CX=CACX = CA , determine the angle ∠VAU\angle VAU .

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