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OME 2015 Problem 2

    In triangle ABCABC , let A′A' is the symmetrical of AA with respect to the circumcenter OO of ABCABC . Prove that:a) The sum of the squares of the tangents segments drawn from AA and A′A' to the incircle of ABCABC equals 4R2−4Rr−2r24R^2-4Rr-2r^2 where RR and rr are the radii of the circumscribed and inscribed circles of ABCABC respectively.b) The circle with center A′A' and radius A′IA'I intersects the circumcircle of ABCABC in a point LL such that AL=AB.ACAL=\sqrt{ AB.AC} where II is the centre of the inscribed circle of ABCABC .

    Dataset text AI-MO AoPS. Quoted with source.

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