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KöMaL 2018 B4958

    The sides of a triangle are aa, bb, cc, the radius of the inscribed circle is rr, and the radius of the circumscribed circle is RR. Prove that if a+b+c=4rRandab+bc+ca=6,a+b+c =\frac{4}{rR} \text{and} \sqrt{ab}+\sqrt{bc}+\sqrt{ca} =6, then R=2rR=2r.

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