olymmath

DE-MO 2002 Problem 5

    Show that the triangle whose angles satisfy the equality sin⁡2A+sin⁡2B+sin⁡2Ccos⁡2A+cos⁡2B+cos⁡2C=2\frac{\sin^2A+\sin^2B+\sin^2C}{\cos^2A+\cos^2B+\cos^2C} = 2 is right angled

    Dataset text AI-MO AoPS. Quoted with source.

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