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CONO-SUR 1991 Problem 6

    Given a positive integrer number nn ( n≠0n\ne 0 ), let f(n)f(n) be the average of all the positive divisors of nn . For example, f(3)=1+32=2f(3)=\frac{1+3}{2}=2 , and f(12)=1+2+3+4+6+126=143f(12)=\frac{1+2+3+4+6+12}{6}=\frac{14}{3} .

    a Prove that n+12≥f(n)≥n\frac{n+1}{2} \ge f(n)\ge \sqrt{n} .

    b Find all nn such that f(n)=919f(n)=\frac{91}{9} .

    Dataset text AI-MO AoPS. Quoted with source.

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