olymmath

KöMaL 2019 B5009

    Given that x2+y2+z2=3x^2+y^2+z^2=3, where xx, yy, zz are positive numbers, prove that 21x+21y+21z≥62^{\tfrac1x} + 2^{\tfrac1y} + 2^{\tfrac1z} \ge 6.

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