olymmath

CN-TST 2012 Problem 13

  • Test 3

In an acute-angled ABCABC , ∠A>60∘\angle A>60^{\circ} , HH is its orthocenter. M,NM,N are two points on AB,ACAB,AC respectively, such that ∠HMB=∠HNC=60∘\angle HMB=\angle HNC=60^{\circ} . Let OO be the circumcenter of triangle HMNHMN . DD is a point on the same side with AA of BCBC such that △DBC\triangle DBC is an equilateral triangle. Prove that H,O,DH,O,D are collinear.

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator cn-tst/2012/p13 · Tag 9RS55WZGZA · Edit this page on GitHub · Keys: j next, k previous