olymmath

APMO 2008 Problem 1

  • Paper

Let ABCA B C be a triangle with ∠A<60∘\angle A<60^{\circ}. Let XX and YY be the points on the sides ABA B and ACA C, respectively, such that CA+AX=CB+BXC A+A X=C B+B X and BA+AY=BC+CYB A+A Y=B C+C Y. Let PP be the point in the plane such that the lines PXP X and PYP Y are perpendicular to ABA B and ACA C, respectively. Prove that ∠BPC<120∘\angle B P C<120^{\circ}.

Dataset text NuminaMath olympiads. Quoted with source.

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