olymmath

CN-SMO 2006

China Southeast Mathematical Olympiad 2006.

Other problems

Problem 1

Suppose a>b>0a>b>0 , f(x)=2(a+b)x+2ab4x+a+bf(x)=\dfrac{2(a+b)x+2ab}{4x+a+b} . Show that there exists an unique positive number xx , such that f(x)=(a13+b132)3f(x)=\left(\dfrac{a^{\frac{1}{3}}+b^{\frac{1}{3}}}{2} \right)^3 .

Problem 2

In △ABC\triangle ABC , ∠ABC=90∘\angle ABC=90^{\circ} . Points D,GD,G lie on side ACAC . Points E,FE, F lie on segment BDBD , such that AE⊥BDAE \perp BD and GF⊥BDGF \perp BD . Show that if BE=EFBE=EF , then ∠ABG=∠DFC\angle ABG=\angle DFC .

Problem 3

There is a standard deck of 5252 cards without jokers. The deck consists of four suits(diamond, club, heart, spade) which include thirteen cards in each. For each suit, all thirteen cards are ranked from " 22 " to " AA " (i.e. 2,3,…,Q,K,A2, 3,\ldots , Q, K, A ). A pair of cards is called a "straight flush" if these two cards belong to the same suit and their ranks are adjacent. Additionally, " AA " and " 22 " are considered to be adjacent (i.e. "A" is also considered as " 11 "). For example, spade AA and spade 22 form a "straight flush"; diamond 1010 and diamond QQ are not a "straight flush" pair. Determine how many ways of picking thirteen cards out of the deck such that all ranks are included but no "straight flush" exists in them.

Problem 4

Given any positive integer nn , let ana_n be the real root of equation x3+xn=1x^3+\dfrac{x}{n}=1 . Prove that (1) an+1>ana_{n+1}>a_n ; (2) ∑i=1n1(i+1)2ai<an\sum_{i=1}^{n}\frac{1}{(i+1)^2a_i} <a_n .

Problem 5

In △ABC\triangle ABC , ∠A=60∘\angle A=60^\circ . ⊙I\odot I is the incircle of △ABC\triangle ABC . ⊙I\odot I is tangent to sides ABAB , ACAC at DD , EE , respectively. Line DEDE intersects line BIBI and CICI at FF , GG respectively. Prove that FG=BC2FG=\frac{BC}{2} .

Problem 6

Find the minimum value of real number mm , such that inequality m(a3+b3+c3)≥6(a2+b2+c2)+1m(a^3+b^3+c^3) \ge 6(a^2+b^2+c^2)+1 holds for all positive real numbers a,b,ca,b,c where a+b+c=1a+b+c=1 .

Problem 7

(1) Find the number of positive integer solutions (m,n,r)(m,n,r) of the indeterminate equation mn+nr+mr=2(m+n+r)mn+nr+mr=2(m+n+r) .(2) Given an integer k(k>1)k (k>1) , prove that indeterminate equation mn+nr+mr=k(m+n+r)mn+nr+mr=k(m+n+r) has at least 3k+13k+1 positive integer solutions (m,n,r)(m,n,r) .

Problem 8

Given a circle with its perimeter equal to nn ( n∈N∗n \in N^* ), the least positive integer PnP_n which satisfies the following condition is called the "number of the partitioned circle": there are PnP_n points ( A1,A2,…,APnA_1,A_2, \ldots ,A_{P_n} ) on the circle; For any integer mm ( 1≤m≤n−11\le m\le n-1 ), there always exist two points Ai,AjA_i,A_j ( 1≤i,j≤Pn1\le i,j\le P_n ), such that the length of arc AiAjA_iA_j is equal to mm . Furthermore, all arcs between every two adjacent points Ai,Ai+1A_i,A_{i+1} ( 1≤i≤Pn1\le i\le P_n , Apn+1=A1A_{p_n+1}=A_1 ) form a sequence Tn=(a1,a2,,,apn)T_n=(a_1,a_2,,,a_{p_n}) called the "sequence of the partitioned circle". For example when n=13n=13 , the number of the partitioned circle P13P_{13} =4, the sequence of the partitioned circle T13=(1,3,2,7)T_{13}=(1,3,2,7) or (1,2,6,4)(1,2,6,4) . Determine the values of P21P_{21} and P31P_{31} , and find a possible solution of T21T_{21} and T31T_{31} respectively.