olymmath

BG-MO 1996 Problem 1

    Sequence {an}\{a_n\} it define a1=1a_1=1 and an+1=ann+nana_{n+1}=\frac{a_n}{n}+\frac{n}{a_n} for all n≥1n\ge 1 Prove that ⌊an2⌋=n\lfloor a_n^2\rfloor=n for all n≥4.n\ge 4.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator bg-mo/1996/p1 · Tag QK6XSTSJRJ · Edit this page on GitHub · Keys: j next, k previous