olymmath

BxMO 2017 Problem 4

    A Benelux n-square (with n≥2n\geq 2 ) is an n×nn\times n grid consisting of n2n^2 cells, each of them containing a positive integer, satisfying the following conditions: ∙\bullet the n2n^2 positive integers are pairwise distinct. ∙\bullet if for each row and each column we compute the greatest common divisor of the nn numbers in that row/column, then we obtain 2n2n different outcomes.

    (a) Prove that, in each Benelux n-square (with n≥2n \geq 2 ), there exists a cell containing a number which is at least 2n2.2n^2. (b) Call a Benelux n-square minimal if all n2n^2 numbers in the cells are at most 2n2.2n^2. Determine all n≥2n\geq 2 for which there exists a minimal Benelux n-square.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator benelux/2017/p4 · Tag TW8944PY4Q · Edit this page on GitHub · Keys: j next, k previous