olymmath

BD-BDMO 2021 Problem 6

    Let ABCABC be an acute-angled triangle. The external bisector of ∠BAC\angle BAC meets the line BCBC at point NN . Let MM be the midpoint of BCBC . PP and QQ are two points on line ANAN such that, ∠PMN=∠MQN=90∘\angle PMN=\angle MQN=90^{\circ} . If PN=5PN=5 and BC=3BC=3 , then the length QAQA can be expressed as ab\frac{a}{b} where aa and bb are co-prime positive integers. What is the value of (a+b)(a+b) ?

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator bd-bdmo/2021/p6 · Tag A6H6S53KYF · Edit this page on GitHub · Keys: j next, k previous