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BALTIC-WAY 1993 Problem 18

    In the triangle ABCABC , ∣AB∣=15,∣BC∣=12,∣AC∣=13|AB|=15,|BC|=12,|AC|=13 . Let the median AMAM and bisector BKBK intersect at point OO , where M∈BC,K∈ACM\in BC,K\in AC . Let OL⊥AB,L∈ABOL\perp AB,L\in AB . Prove that ∠OLK=∠OLM\angle OLK=\angle OLM .

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