olymmath

INMO 2007 Problem 1

  • Answer

In a triangle ABCA B C right-angled at CC, the median through BB bisects the angle between BAB A and the bisector of ∠B\angle B. Prove that

52<ABBC<3\frac{5}{2}<\frac{A B}{B C}<3

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

\frac{5}{2}<\frac{c}{a}<3

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator in-inmo/2007/p1 · Tag A5J97ZQEZG · Edit this page on GitHub · Keys: j next, k previous