olymmath

BALKAN-SL 2011 A1

    Given real numbers x,y,zx,y,z such that x+y+z=0x+y+z=0, show that x(x+2)2x2+1+y(y+2)2y2+1+z(z+2)2z2+1≥0\dfrac{x(x+2)}{2x^2+1}+\dfrac{y(y+2)}{2y^2+1}+\dfrac{z(z+2)}{2z^2+1}\ge 0

    When does equality hold?

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