Home Competitions AUSTRIAN-POLISH 1992 Problem 6
AUSTRIAN-POLISH 1992 Problem 6
A function f : Z → Z f: Z \to Z f : Z → Z f ( 92 + x ) = f ( 92 − x ) f (92 + x) = f (92 - x) f ( 92 + x ) = f ( 92 − x ) f ( 19 ⋅ 92 + x ) = f ( 19 ⋅ 92 − x ) f (19 \cdot 92 + x) = f (19 \cdot 92 - x) f ( 19 ⋅ 92 + x ) = f ( 19 ⋅ 92 − x ) 19 ⋅ 92 = 1748 19 \cdot 92 = 1748 19 ⋅ 92 = 1748 f ( 1992 + x ) = f ( 1992 − x ) f (1992 + x) = f (1992 - x) f ( 1992 + x ) = f ( 1992 − x ) x x x 92 92 92
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