olymmath

ÖMO 2011

Austrian Mathematical Olympiad 2011.

Day 1

Problem 1

  • Day 1

Every brick has 55 holes in a line. The holes can be filled with bolts (fi tting in one hole) and braces (fi tting into two neighboring holes). No hole may remain free. One puts nn of these bricks in a line to form a pattern from left to right. In this line no two braces and no three bolts may be adjacent. How many diff erent such patterns can be produced with nn bricks?

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Problem 2

  • Day 1

We consider permutations ff of the set N\mathbb{N} of non-negative integers, i.e. bijective maps ff from N\mathbb{N} to N\mathbb{N} , with the following additional properties: f(f(x))=xand∣f(x)−x∣⩽3for all x∈N.f(f(x)) = x \text{and} \left| f(x)-x\right| \leqslant 3 \text{for all } x \in\mathbb{N}\text{.} Further, for all integers n>42n > 42 , M(n)=1n+1∑j=0n∣f(j)−j∣<2,011.\left.M(n)=\frac{1}{n+1}\sum_{j=0}^n \left|f(j)-j\right|<2,011\text{.}\right. Show that there are infinitely many natural numbers KK such that ff maps the set {n∣0⩽n⩽K}\left\{ n\mid 0\leqslant n\leqslant K\right\} onto itself.

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Problem 3

  • Day 1

We are given a non-isosceles triangle ABCABC with incenter II . Show that the circumcircle kk of the triangle AIBAIB does not touch the lines CACA and CBCB . Let PP be the second point of intersection of kk with CACA and let QQ be the second point of intersection of kk with CBCB . Show that the four points AA , BB , PP and QQ (not necessarily in this order) are the vertices of a trapezoid.

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Day 2

Problem 4

  • Day 2

Determine all pairs (a,b)(a,b) of non-negative integers, such that ab+ba^b+b divides a2b+2ba^{2b}+2b . (Remark: 00=10^0=1 .)

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Problem 5

  • Day 2

Let kk and nn be positive integers. Show that if xjx_j ( 1⩽j⩽n1\leqslant j\leqslant n ) are real numbers with ∑j=1n1xj2k+k=1k\sum_{j=1}^n\frac{1}{x_j^{2^k}+k}=\frac{1}{k} , then ∑j=1n1xj2k+1+k+2⩽1k+1.\sum_{j=1}^n\frac{1}{x_j^{2^{k+1}}+k+2}\leqslant\frac{1}{k+1}\text{.}

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Problem 6

  • Day 2

Two circles k1k_1 and k2k_2 with radii r1r_1 and r2r_2 touch each outside at point QQ . The other endpoints of the diameters through QQ are PP on k1k_1 and RR on k2k_2 . We choose two points AA and BB , one on each of the arcs PQPQ of k1k_1 . ( PBQAPBQA is a convex quadrangle.) Further, let CC be the second point of intersection of the line AQAQ with k2k_2 and let DD be the second point of intersection of the line BQBQ with k2k_2 . The lines PBPB and RCRC intersect in UU and the lines PAPA and RDRD intersect in VV . Show that there is a point ZZ that lies on all of these lines UVUV .

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