olymmath

APMO 2012

Asian Pacific Mathematics Olympiad 2012.

Paper

Problem 1

  • Paper

Let PP be a point in the interior of a triangle ABCABC , and let D,E,FD, E, F be the point of intersection of the line APAP and the side BCBC of the triangle, of the line BPBP and the side CACA , and of the line CPCP and the side ABAB , respectively. Prove that the area of the triangle ABCABC must be 66 if the area of each of the triangles PFA,PDBPFA, PDB and PECPEC is 11 .

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Problem 2

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Into each box of a 2012×20122012 \times 2012 square grid, a real number greater than or equal to 00 and less than or equal to 11 is inserted. Consider splitting the grid into 22 non-empty rectangles consisting of boxes of the grid by drawing a line parallel either to the horizontal or the vertical side of the grid. Suppose that for at least one of the resulting rectangles the sum of the numbers in the boxes within the rectangle is less than or equal to 11 , no matter how the grid is split into 22 such rectangles. Determine the maximum possible value for the sum of all the 2012×20122012 \times 2012 numbers inserted into the boxes.

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Problem 3

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Determine all the pairs (p,n)(p , n ) of a prime number pp and a positive integer nn for which np+1pn+1\frac{ n^p + 1 }{p^n + 1} is an integer.

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Problem 4

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Let ABCABC be an acute triangle. Denote by DD the foot of the perpendicular line drawn from the point AA to the side BCBC , by MM the midpoint of BCBC , and by HH the orthocenter of ABCABC . Let EE be the point of intersection of the circumcircle Γ\Gamma of the triangle ABCABC and the half line MHMH , and FF be the point of intersection (other than EE ) of the line EDED and the circle Γ\Gamma . Prove that BFCF=ABAC\tfrac{BF}{CF} = \tfrac{AB}{AC} must hold.

(Here we denote XYXY the length of the line segment XYXY .)

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Problem 5

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Let nn be an integer greater than or equal to 22 . Prove that if the real numbers a1,a2,⋯ ,ana_1 , a_2 , \cdots , a_n satisfy a12+a22+⋯+an2=na_1 ^2 + a_2 ^2 + \cdots + a_n ^ 2 = n , then ∑1≤i<j≤n1n−aiaj≤n2\sum_{1 \le i < j \le n} \frac{1}{n- a_i a_j} \le \frac{n}{2} must hold.

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