AMC 8 2019 Problem 15

On a beach $50$ people are wearing sunglasses and $35$ people are wearing caps. Some people are wearing both sunglasses and caps. If one of the people wearing a cap is selected at random, the probability that this person is also wearing sunglasses is $\frac{2}{5}$. If instead, someone wearing sunglasses is selected at random, what is the probability that this person is also wearing a cap? $\textbf{(A) }\frac{14}{85} \textbf{(B) }\frac{7}{25} \textbf{(C) }\frac{2}{5} \textbf{(D) }\frac{4}{7} \textbf{(E) }\frac{7}{10}$