AMC 8 1994 Problem 7

If $\angle A = 60^\circ$, $\angle E = 40^\circ$ and $\angle C = 30^\circ$, then $\angle BDC =$

$\text{(A)}\ 40^\circ \text{(B)}\ 50^\circ \text{(C)}\ 60^\circ \text{(D)}\ 70^\circ \text{(E)}\ 80^\circ$