AHSME 1993 Problem 2

In $\triangle ABC$, $\angle A=55^\circ$, $\angle C=75^\circ, D$ is on side $\overline{AB}$ and $E$ is on side $\overline{BC}$. If $DB=BE$, then $\angle{BED} =$

$\text{(A) } 50^\circ \text{(B) } 55^\circ \text{(C) } 60^\circ \text{(D) } 65^\circ \text{(E) } 70^\circ$