AMC 8 1994 Problem 13

The number halfway between $\dfrac{1}{6}$ and $\dfrac{1}{4}$ is $\text{(A)}\ \dfrac{1}{10} \text{(B)}\ \dfrac{1}{5} \text{(C)}\ \dfrac{5}{24} \text{(D)}\ \dfrac{7}{24} \text{(E)}\ \dfrac{5}{12}$