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AMC 8 1993 Problem 16

  • Paper

11+12+13=\frac{1}{1+\frac{1}{2+\frac{1}{3}}}= (A) 16(B) 310(C) 710(D) 56(E) 103\text{(A)}\ \dfrac{1}{6} \text{(B)}\ \dfrac{3}{10} \text{(C)}\ \dfrac{7}{10} \text{(D)}\ \dfrac{5}{6} \text{(E)}\ \dfrac{10}{3}

Dataset text NuminaMath-1.5. Quoted with source.

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\frac{7}{10}

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