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AMC 8 1993 Problem 7

  • Paper

33+33+33=3^3+3^3+3^3 = (A) 34(B) 93(C) 39(D) 273(E) 327\text{(A)}\ 3^4 \text{(B)}\ 9^3 \text{(C)}\ 3^9 \text{(D)}\ 27^3 \text{(E)}\ 3^{27}

Dataset text NuminaMath-1.5. Quoted with source.

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3^4

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