olymmath

AMC 12 2003b Problem 19

  • Paper

Let SS be the set of permutations of the sequence 1,2,3,4,51,2,3,4,5 for which the first term is not 11. A permutation is chosen randomly from SS. The probability that the second term is 22, in lowest terms, is a/ba/b. What is a+ba+b?

(A) 5(B) 6(C) 11(D) 16(E) 19\mathrm{(A)}\ 5 \mathrm{(B)}\ 6 \mathrm{(C)}\ 11 \mathrm{(D)}\ 16 \mathrm{(E)}\ 19

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

E

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2003b/p19 · Tag AR7MG1T31P · Edit this page on GitHub · Keys: j next, k previous