olymmath

RU-ALLRUSSIAN 1984 Problem 10

    x1<x2<x3<…<xn\mathrm{x_1< x_2< x_3< \ldots < x_n} . yi\mathrm{y_i} is a permutation of the xi\mathrm{x_i} . We have that x1+y1<x2+y2<…<xn+\mathrm{x_1 + y_1< x_2 + y_2< \ldots < x_n + } yn\mathrm{y_n} . Prove that xi=yi\mathrm{x_i = y_i} .

    Dataset text NuminaMath olympiads. Quoted with source.

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