AMC 10 2017b Problem 15

Rectangle $ABCD$ has $AB=3$ and $BC=4$. Point $E$ is the foot of the perpendicular from $B$ to diagonal $\overline{AC}$. What is the area of $\triangle AED$? $\textbf{(A)}\ 1 \textbf{(B)}\ \frac{42}{25} \textbf{(C)}\ \frac{28}{15} \textbf{(D)}\ 2 \textbf{(E)}\ \frac{54}{25}$