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AIME 2025b Problem 13

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Let the sequence of rationals x1,x2,…x_1,x_2,\dots be defined such that x1=2511x_1=\frac{25}{11} and xk+1=13(xk+1xk−1).x_{k+1}=\frac{1}{3}\left(x_k+\frac{1}{x_k}-1\right).x2025x_{2025} can be expressed as mn\frac{m}{n} for relatively prime positive integers mm and nn. Find the remainder when m+nm+n is divided by 10001000.

Dataset text AIME 1983 to 2026. Quoted with source.

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