olymmath

AIME 2010a Problem 14

  • Paper
  • Answer

For each positive integer nn, let f(n)=∑k=1100⌊log⁡10(kn)⌋f(n) = \sum_{k = 1}^{100} \lfloor \log_{10} (kn) \rfloor. Find the largest value of nn for which f(n)≤300f(n) \le 300. Note: ⌊x⌋\lfloor x \rfloor is the greatest integer less than or equal to xx.

Dataset text AIME 1983 to 2026. Quoted with source.

Show the answer

109

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator aime/2010a/p14 · Tag 5CK36NH4EW · Edit this page on GitHub · Keys: j next, k previous