olymmath

AIME 2010a Problem 15

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In △ABC\triangle{ABC} with AB=12AB = 12, BC=13BC = 13, and AC=15AC = 15, let MM be a point on AC‾\overline{AC} such that the incircles of △ABM\triangle{ABM} and △BCM\triangle{BCM} have equal radii. Then AMCM=pq\frac{AM}{CM} = \frac{p}{q}, where pp and qq are relatively prime positive integers. Find p+qp + q.

Dataset text AIME 1983 to 2026. Quoted with source.

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