AIME 1991 Problem 11
- Paper
- Answer
Twelve congruent disks are placed on a circle of radius 1 in such a way that the twelve disks cover , no two of the disks overlap, and so that each of the twelve disks is tangent to its two neighbors. The resulting arrangement of disks is shown in the figure below. The sum of the areas of the twelve disks can be written in the from , where are positive integers and is not divisible by the square of any prime. Find .
Dataset text AIME 1983 to 2026. Quoted with source.
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