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AHSME 1999 Problem 20

    The sequence a1,a2,a3,…a_{1},a_{2},a_{3},\ldots satisfies a1=19,a9=99a_{1} = 19,a_{9} = 99, and, for all n≥3n\geq 3, ana_{n} is the arithmetic mean of the first n−1n - 1 terms. Find a2a_2. (A) 29(B) 59(C) 79(D) 99(E) 179\textrm{(A)} \ 29 \textrm{(B)} \ 59 \textrm{(C)} \ 79 \textrm{(D)} \ 99 \textrm{(E)} \ 179

    Dataset text NuminaMath-1.5. Quoted with source.

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    179

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