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AMC 12 2007a Problem 7

  • Paper

Let a,b,c,da, b, c, d, and ee be five consecutive terms in an arithmetic sequence, and suppose that a+b+c+d+e=30a+b+c+d+e=30. Which of a,b,c,d,a, b, c, d, or ee can be found?

(A) a(B) b(C) c(D) d(E) e\textrm{(A)} \ a \textrm{(B)}\ b \textrm{(C)}\ c \textrm{(D)}\ d \textrm{(E)}\ e

Dataset text AMC 12 2000 to 2025. Quoted with source.

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C

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