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AHSME 1996 Problem 3

    (3!)!3!=\frac{(3!)!}{3!}= (A) 1(B) 2(C) 6(D) 40(E) 120\text{(A)}\ 1 \text{(B)}\ 2 \text{(C)}\ 6 \text{(D)}\ 40 \text{(E)}\ 120

    Dataset text NuminaMath-1.5. Quoted with source.

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    120

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