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AHSME 1979 Problem 20

    If a=12a=\tfrac{1}{2} and (a+1)(b+1)=2(a+1)(b+1)=2 then the radian measure of arctan⁡a+arctan⁡b\arctan a + \arctan b equals (A) π2(B) π3(C) π4(D) π5(E) π6\textbf{(A) }\frac{\pi}{2} \textbf{(B) }\frac{\pi}{3} \textbf{(C) }\frac{\pi}{4} \textbf{(D) }\frac{\pi}{5} \textbf{(E) }\frac{\pi}{6}

    Dataset text NuminaMath-1.5. Quoted with source.

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    C

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